document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620188>Question 620188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a 80ml solution that is 20% acid by volume, how many mL should I remove and replace with pure 100% acid to obtain a final solution of 80ml that is 40% acid by volume? What is the equation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389973 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have a 80ml solution that is 20% acid by volume, how many mL should I remove and replace with pure 100% acid to obtain a final solution of 80ml that is 40% acid by volume? What is the equation?<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid - acid + acid = acid<BR>\n" );
document.write( "0.20*80 - 0.20x + x = 0.40*80<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "20*80 - 20x + 100x = 40*80<BR>\n" );
document.write( "80x = 20*80<BR>\n" );
document.write( "x = 20 ml (amt. to remove and replace)<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );