document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=620060>Question 620060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many grams of pure silver must a silversmith mix with a 45% silver alloy to produce 200 grams of a 50% alloy?\r<BR>\n" );
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document.write( "I just want so help setting the promblem up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389960 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many grams of pure silver must a silversmith mix with a 45% silver alloy to produce 200 grams of a 50% alloy? <BR>\n" );
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document.write( "Let s = amt of pure silver required to accomplish this<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(200-s) = amt of 45% alloy required<BR>\n" );
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document.write( "1.00s + .45(200-s) = .50(200) </SPAN>\n" );
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