document.write( "Question 620145: Hello, I need help in solving this problem:\r
\n" ); document.write( "\n" ); document.write( "A plane flew 150 kilometers with a 30 km/hr tailwind, then turned into the wind
\n" ); document.write( "and flew for another 65 kilometers. If the wind and the plane’s airspeed were
\n" ); document.write( "constant and the entire trip took 30 minutes, what was the plane’s airspeed?
\n" ); document.write( "(Ignore the time needed to turn the plane around).\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #389944 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
Let s = the plane's airspeed
\n" ); document.write( "The total time of the trip is 30 mins = 1/2 hr; the speed of the wind = 30 km/hr
\n" ); document.write( "Since t = d/v, we can write the following for the total time of the trip:
\n" ); document.write( "150/(s+30) + 65/(s-30) = 0.5
\n" ); document.write( "Combine fractions using the common denominator, and cross-multiply:
\n" ); document.write( "150(s-30) + 65(s+30) = 0.5(s^2-900)
\n" ); document.write( "Simplify and collect terms:
\n" ); document.write( "s^2 - 430s + 4200 = 0
\n" ); document.write( "This can be factored as
\n" ); document.write( "(s-10)(s-420) = 0
\n" ); document.write( "The solutions are s = 10, s = 420
\n" ); document.write( "Since the speed of the plane cannot be less than the wind speed, we take the 2nd solution.
\n" ); document.write( "So s = 420 km/hr
\n" ); document.write( "Check:
\n" ); document.write( "150/450 + 65/390 = 1/3 + 1/6 = 3/6 = 1/2
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