document.write( "Question 619309: x² + 12x + 11
\n" ); document.write( "I'm assuming you meant:
\n" ); document.write( "x² + 12x + 11 = 0 (Yes, the zero matters ;-)
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Algebra.Com's Answer #389927 by mathsmiles(68)\"\" \"About 
You can put this solution on YOUR website!
x² + 12x + 11 = 0
\n" ); document.write( "(x + ...) (x + ... ) = 0
\n" ); document.write( "We need to find two factors of 11 whose sum is 12. That's rather easy since 11 is prime. It's only factors are 1 and itself - 11.
\n" ); document.write( "(x + 11)(x + 1) = 0
\n" ); document.write( "Now solve each of these separately. That is, at least one of these two factors must be zero for the whole equation to be equal to zero.
\n" ); document.write( "(x+11) = 0
\n" ); document.write( "Subtract 11 from both sides ...
\n" ); document.write( "x = -11
\n" ); document.write( "Now the other ...
\n" ); document.write( "x+1 = 0
\n" ); document.write( "Subtract 1 from both sides ...
\n" ); document.write( "x = -1\r
\n" ); document.write( "\n" ); document.write( "So both -11 and -1 are possible solutions for x. Let's check ... \r
\n" ); document.write( "\n" ); document.write( "x² + 12x + 11 = 0
\n" ); document.write( "(-11)^2 + 12(-11) + 11 = 0
\n" ); document.write( "121 - 132 + 11 = 0
\n" ); document.write( "0 = 0 Check!\r
\n" ); document.write( "\n" ); document.write( "x² + 12x + 11 = 0
\n" ); document.write( "(-1)^2 + 12(-1) + 11 = 0
\n" ); document.write( "1 - 12 + 11 = 0
\n" ); document.write( "0 = 0 Check!
\n" ); document.write( "
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