document.write( "Question 620130: A canoe takes 7 hours to travel 48 kilometres down a river and back.The rate of the current of the river is 2 kilometres per hour.Find the rate of the canoe in still(calm) water. \n" ); document.write( "
Algebra.Com's Answer #389922 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "A canoe takes 7 hours to travel 48 km down a river and back.The rate of the current of the river is 2 kmph.
\n" ); document.write( "Find the rate\"highlight%28r%29\"of the canoe in still(calm) water.
\n" ); document.write( " D =rt or D/r = t
\n" ); document.write( " \"48%2F%28r%2B2%29+++%2B48%2F%28r-2%29+=+7hr\" |Multiplying thru by (r+2)(r-2)so as all denominators = 1
\n" ); document.write( " 48(r-2) + 48(r+2) = 7(r+2)(r-2)
\n" ); document.write( " 96r = 7(r^2 - 4)
\n" ); document.write( " 7r^2 - 96r - 28 = 0
\n" ); document.write( " (7r+2)(r - 14) = 0 |throwing out negative solution for rate
\n" ); document.write( " r = 14 kmph is the speed of the canoe in still(calm) water.
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " \"+48km%2F16kmph+%2B48km%2F12kmph\" = 3hr + 4hr = 7hr
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