document.write( "Question 620031: Log(9+9x)-log(11-x)=2 \n" ); document.write( "
Algebra.Com's Answer #389884 by nerdybill(7384)\"\" \"About 
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Log(9+9x)-log(11-x)=2
\n" ); document.write( "Log(9+9x)/(11-x)=2
\n" ); document.write( "(9+9x)/(11-x)=10^2
\n" ); document.write( "(9+9x)/(11-x)=100
\n" ); document.write( "(9+9x)=100(11-x)
\n" ); document.write( "9+9x=1100-100x
\n" ); document.write( "9+109x=1100
\n" ); document.write( "109x=1091
\n" ); document.write( "x = 1091/109
\n" ); document.write( "x = 10.009\r
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