document.write( "Question 619971: fix it fast plumbing charges $25 for a house call and $50 for each hour spent on the job. do it right plumbing charges $35 for a house call and $45 for each hour spent on the job. how many hours must be spent on the job in order for the charges of the two plumbingcompanies to be equal?
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Algebra.Com's Answer #389869 by dragonwalker(73)![]() ![]() ![]() You can put this solution on YOUR website! let us call the number of hours on the job as 'h'\r \n" ); document.write( "\n" ); document.write( "For each company the cost of a job is the initial house call fee plus the hourly fee multiplied by the number of hours on the job. \n" ); document.write( "For Fif the cost of a job can be written as 25 + 50h \n" ); document.write( "For DiR the cost of a job can be written as 35 + 45h\r \n" ); document.write( "\n" ); document.write( "For each fee to be equal we can write it as follows:\r \n" ); document.write( "\n" ); document.write( "25 + 50h = 35 + 45h\r \n" ); document.write( "\n" ); document.write( "rearrange, remembering to change the sign if the value moves to the other side of the equation:\r \n" ); document.write( "\n" ); document.write( "50h - 45h = 35 - 25\r \n" ); document.write( "\n" ); document.write( "5h = 10\r \n" ); document.write( "\n" ); document.write( "solve for h by dividing both sides by 5: \n" ); document.write( "5h/5 = 10/5\r \n" ); document.write( "\n" ); document.write( "h=2 \n" ); document.write( "so the number of hours on a job for the cost to be the same is 2 hours.\r \n" ); document.write( "\n" ); document.write( "To check we can substitute the value of h into the equations for each company and see if they are the same: \n" ); document.write( "For Fif the cost of a job can be written as 25 + 50h = 25 + 2(50) = 125!!! \n" ); document.write( "For DiR the cost of a job can be written as 35 + 45h = 35 + 2(45) = 125!!! \n" ); document.write( " |