document.write( "Question 619776: At 9 am a car leaves a city traveling west. An good and half later a faster car leaves the same city traveling east. At 2 pm the two cars are 410 miles apart. If the slower car travels at 2/3 the speed of the faster car, what is the speed of the fast car \n" ); document.write( "
Algebra.Com's Answer #389862 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At 9 am a car leaves a city traveling west. \n" ); document.write( "Assume you mean \n" ); document.write( " An HOUR and half later a faster car leaves the same city traveling east. \n" ); document.write( " At 2 pm the two cars are 410 miles apart. \n" ); document.write( " If the slower car travels at 2/3 the speed of the faster car, what is the speed of the fast car \n" ); document.write( ": \n" ); document.write( "Let s = speed of the fast car \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Find the travel time of the slower car: 9 am to 2 pm = 5 hrs \n" ); document.write( "Find the travel time of the faster car: 5 - 1.5 = 3.5 hrs \n" ); document.write( ": \n" ); document.write( "WRite a distance equation; dist = speed * time \n" ); document.write( "slow car dist + fast car dist = 410 miles \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply by 3 \n" ); document.write( "10s + 10.5s = 1230 \n" ); document.write( "20.5s = 1230 \n" ); document.write( "s = \n" ); document.write( "s = 60 mph is the fast car \n" ); document.write( "then \n" ); document.write( " |