document.write( "Question 619776: At 9 am a car leaves a city traveling west. An good and half later a faster car leaves the same city traveling east. At 2 pm the two cars are 410 miles apart. If the slower car travels at 2/3 the speed of the faster car, what is the speed of the fast car \n" ); document.write( "
Algebra.Com's Answer #389862 by ankor@dixie-net.com(22740)\"\" \"About 
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At 9 am a car leaves a city traveling west.
\n" ); document.write( "Assume you mean
\n" ); document.write( " An HOUR and half later a faster car leaves the same city traveling east.
\n" ); document.write( " At 2 pm the two cars are 410 miles apart.
\n" ); document.write( " If the slower car travels at 2/3 the speed of the faster car, what is the speed of the fast car
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of the fast car
\n" ); document.write( "then
\n" ); document.write( "\"2%2F3\"s = speed of the slower car
\n" ); document.write( ":
\n" ); document.write( "Find the travel time of the slower car: 9 am to 2 pm = 5 hrs
\n" ); document.write( "Find the travel time of the faster car: 5 - 1.5 = 3.5 hrs
\n" ); document.write( ":
\n" ); document.write( "WRite a distance equation; dist = speed * time
\n" ); document.write( "slow car dist + fast car dist = 410 miles
\n" ); document.write( "\"2%2F3\"s * 5 + 3.5s = 410
\n" ); document.write( "\"10%2F3\"s + 3.5s = 410
\n" ); document.write( "Multiply by 3
\n" ); document.write( "10s + 10.5s = 1230
\n" ); document.write( "20.5s = 1230
\n" ); document.write( "s = \"1230%2F20.5\"
\n" ); document.write( "s = 60 mph is the fast car
\n" ); document.write( "then
\n" ); document.write( "\"2%2F3\"*60 = 40 mph is the slow car
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