document.write( "Question 619927: Hello. I am sorry for the bother, but please help me. During the summer, I must study algebra so that I can (re)take the test for this one charter school. However, because I am so bad at math, I cannot complete this alone. For today, I just need help understanding the whole concept of \"equations\". Particulary, I need help on simple things like 3x+6=30... solve for x. Again, I am very sorry for this immediate disturbance. I have tried +6 on both sides, but I do not know what to do next. I must pass their test. Yet, I am still stuck on this simple problem... please help! Thank you. \n" ); document.write( "
Algebra.Com's Answer #389858 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! You don't add 6 to both sides. You want to undo that +6 on the left side. So you subtract 6 from both sides\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to go from\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x+6 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x+6 -6 = 30 -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then notice how 6-6 on the left side becomes 0 and it goes away. On the right side, 30-6 becomes 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we then get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x = 24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now divide both sides by 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x/3 = 24/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the answer is x = 8 \n" ); document.write( " |