document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619913>Question 619913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorcycle daredevil is planning a stunt to perform at a county fair. A ramp must be built to give him a 20% grade, or slope. If the vertical height at the end of the ramp must be 15 ft to assure that the stunt is a success, what must be the length of the horizontal run? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389852 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope Grade = (Rise/Run)*100\r<BR>\n" );
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document.write( "20 = (15/x)*100\r<BR>\n" );
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document.write( "20 = 1500/x\r<BR>\n" );
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document.write( "20x = 1500\r<BR>\n" );
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document.write( "x = 1500/20\r<BR>\n" );
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document.write( "x = 75\r<BR>\n" );
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document.write( "So the length of the horizontal run must be <font color=\"red\">75 feet</font> </SPAN>\n" );
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