document.write( "Question 619794: 5.
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document.write( "How many pounds of an $83 per pound substance must be mixed with an $11 per pound substance to get 240 lbs of an alloy which will cost $28 per pound? Round to the nearest pound. \n" );
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Algebra.Com's Answer #389838 by Alan3354(69443) You can put this solution on YOUR website! 5. \n" ); document.write( "How many pounds of an $83 per pound substance must be mixed with an $11 per pound substance to get 240 lbs of an alloy which will cost $28 per pound? Round to the nearest pound. \n" ); document.write( "-------------------- \n" ); document.write( "Do it like this one: \n" ); document.write( "if a 14% acid solution is mixed with a 19% acid solution to produce 45 gallons of a 15% acid solution how much (in gallons) of each solution should be used? \n" ); document.write( "-------------- \n" ); document.write( "f = 14% \n" ); document.write( "n = 19% \n" ); document.write( "---- \n" ); document.write( "f + n = 45 (total gallons) \n" ); document.write( "14f + 19n = 15*45 (total acid) \n" ); document.write( "----- \n" ); document.write( "n = 45 - f \n" ); document.write( "Sub for n \n" ); document.write( "14f + 19*(45-f) = 675 \n" ); document.write( "14f + 855 - 19f = 675 \n" ); document.write( "-5f = -180 \n" ); document.write( "f = 36 gallons of 14% \n" ); document.write( "n = 9 gallons of 19% \n" ); document.write( " |