document.write( "Question 57283: This is a calculus question:\r
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\n" ); document.write( "Find all the points of inflection (concavity)
\n" ); document.write( "f(x)= x^4-18x^2+4
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Algebra.Com's Answer #38982 by stanbon(75887)\"\" \"About 
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f(x)= x^4-18x^2+4
\n" ); document.write( "f' = 4x^3-36x
\n" ); document.write( "f''=12x^2-36
\n" ); document.write( "Let f''=0:
\n" ); document.write( "12x^2-36=0
\n" ); document.write( "x^2-3=0
\n" ); document.write( "x=sqrt3 or x=-sqrt3
\n" ); document.write( "These are the candidate values:
\n" ); document.write( "Now, does f'' change sign at
\n" ); document.write( "x=sqrt3 or at x=-sqrt3
\n" ); document.write( "Recall f''=12x^2-36
\n" ); document.write( "As x approches sqrt3 from the left
\n" ); document.write( "f'' is negative because 12x^2 will be
\n" ); document.write( "less than 36.
\n" ); document.write( "As x approches sqrt3 from the right f''
\n" ); document.write( "is positive because 12x^2 will be greater
\n" ); document.write( "than 36.
\n" ); document.write( "So there is a point of inflection at x=sqrt3.
\n" ); document.write( "---------
\n" ); document.write( "The same logic will hold for x=-sqrt3 because
\n" ); document.write( "of the term 12x^2 .
\n" ); document.write( "You have two points of inflection: x=sqrt3 and
\n" ); document.write( "x=-sqrt3
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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