document.write( "Question 57283: This is a calculus question:\r
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document.write( "Please Please Help!
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document.write( "Find all the points of inflection (concavity)
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document.write( "f(x)= x^4-18x^2+4
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Algebra.Com's Answer #38982 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! f(x)= x^4-18x^2+4 \n" ); document.write( "f' = 4x^3-36x \n" ); document.write( "f''=12x^2-36 \n" ); document.write( "Let f''=0: \n" ); document.write( "12x^2-36=0 \n" ); document.write( "x^2-3=0 \n" ); document.write( "x=sqrt3 or x=-sqrt3 \n" ); document.write( "These are the candidate values: \n" ); document.write( "Now, does f'' change sign at \n" ); document.write( "x=sqrt3 or at x=-sqrt3 \n" ); document.write( "Recall f''=12x^2-36 \n" ); document.write( "As x approches sqrt3 from the left \n" ); document.write( "f'' is negative because 12x^2 will be \n" ); document.write( "less than 36. \n" ); document.write( "As x approches sqrt3 from the right f'' \n" ); document.write( "is positive because 12x^2 will be greater \n" ); document.write( "than 36. \n" ); document.write( "So there is a point of inflection at x=sqrt3. \n" ); document.write( "--------- \n" ); document.write( "The same logic will hold for x=-sqrt3 because \n" ); document.write( "of the term 12x^2 . \n" ); document.write( "You have two points of inflection: x=sqrt3 and \n" ); document.write( "x=-sqrt3 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |