document.write( "Question 57272This question is from textbook
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document.write( ": We are asked to graph the following quadradic equation -f(x)=X^2-3x+1.\r
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document.write( "AS I graph it the parabola opens up, 3 spaces up and is moved over 1 space to the right. However according to the book it opens down and over 1 and up the y-axis 3 spaces. If X^2 is positive I thought it opened up?!?! where am I going wrong or what do I not understand?? Any help will be appreciated on this.\r
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document.write( "Thanks in advance. \n" );
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Algebra.Com's Answer #38980 by stanbon(75887) ![]() You can put this solution on YOUR website! -f(x)=X^2-3x+1. \n" ); document.write( "You are given the formula for negative f(x) \n" ); document.write( "If you multiply each side by minus-one you \n" ); document.write( "will get: \n" ); document.write( "f(x)=-x^2+3x+1 \n" ); document.write( "Now you should see that it opens down because \n" ); document.write( "of the negative coefficient of x^2 \n" ); document.write( "If you complete the square you get: \n" ); document.write( "y-1+?=-(x^2-3x+? \n" ); document.write( "y-1-(3/2)^2=-(x^2-3x+(3/2)^2) \n" ); document.write( "y-(13/4)=-(x-(3/2))^2 \n" ); document.write( "So the vertex is at (3/2,13,4) \n" ); document.write( "Hope this helps. \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |