document.write( "Question 619791: 3.
\n" ); document.write( "How many kilograms of pure salt must be added to 7 kg of a 30% salt solution in order to produce a 60% solution? Remember that pure salt is a 100% solution of salt. Round your answer to the nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "I used the equation (%1)(A1)+(%2)(A2) = (%M)(A1)
\n" ); document.write( "I keep getting the wrong answers \n" ); document.write( "

Algebra.Com's Answer #389793 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "How many kilograms of pure salt must be added to 7 kg of a 30% salt solution 
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document.write( "in order to produce a 60% solution?
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document.write( "  salt  = salt
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document.write( "(%1)(A1)+(%2)(A2)  Yes! that part is correct.  
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document.write( "Note: 100% = 1.00
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document.write( "  1· x + .30·7kg = .60(x+7)   ||Note:  need to same 'kgs' on each side of EQ
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document.write( "Solving for x:
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document.write( "  1· x + .30·7kg = .60x+ .60·7kg
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document.write( "      .4x = .30·7kg
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document.write( "        x = .30·7kg/.4 = 5.25kg of pure salt
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