document.write( "Question 619765: please help me solve this equation\r
\n" ); document.write( "\n" ); document.write( "log (x+15) -log x= 2
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Algebra.Com's Answer #389788 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log (x+15) -log x = 2
\n" ); document.write( "log (x+15)/x = 2
\n" ); document.write( "(x+15)/x = 10^2
\n" ); document.write( "(x+15)/x = 100
\n" ); document.write( "x+15 = 100x
\n" ); document.write( "15 = 99x
\n" ); document.write( "15/99 = x
\n" ); document.write( "5/33 = x
\n" ); document.write( "0.152 = x
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