document.write( "Question 619765: please help me solve this equation\r
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document.write( "log (x+15) -log x= 2 \n" );
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Algebra.Com's Answer #389788 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! log (x+15) -log x = 2 \n" ); document.write( "log (x+15)/x = 2 \n" ); document.write( "(x+15)/x = 10^2 \n" ); document.write( "(x+15)/x = 100 \n" ); document.write( "x+15 = 100x \n" ); document.write( "15 = 99x \n" ); document.write( "15/99 = x \n" ); document.write( "5/33 = x \n" ); document.write( "0.152 = x \n" ); document.write( " \n" ); document.write( " |