document.write( "Question 57256: Please help! I think this may be missing something, not sure though.
\n" ); document.write( "Boat is traveling from A to B at 33mph
\n" ); document.write( "Plane is also traveling from same A to B at 605mph.
\n" ); document.write( "Plane takes 104 hours LESS to make the trip.
\n" ); document.write( "How far apart are A and B.
\n" ); document.write( "It does not say if they left at the same time, but have to assume they did.
\n" ); document.write( "It does not say for how long either were traveling.
\n" ); document.write( "Thanks in advance!
\n" ); document.write( "

Algebra.Com's Answer #38968 by Scriptor(36)\"\" \"About 
You can put this solution on YOUR website!
Hello,\r
\n" ); document.write( "\n" ); document.write( "I will assume that they start at the same time.\r
\n" ); document.write( "\n" ); document.write( "Remember that: Speed * Time = Distance\r
\n" ); document.write( "\n" ); document.write( "Call t the time that the plane needs to get from A to B.\r
\n" ); document.write( "\n" ); document.write( "Call x the distance between A and B.\r
\n" ); document.write( "\n" ); document.write( "Then we have that: 605*t = x
\n" ); document.write( "But we also know that 33*(t+104) = x
\n" ); document.write( "(because the boat takes 104 hours more in time)\r
\n" ); document.write( "\n" ); document.write( "This gives us 605*t = x = 33*(t+104)\r
\n" ); document.write( "\n" ); document.write( "605t = 33t + 3432\r
\n" ); document.write( "\n" ); document.write( "t= 6\r
\n" ); document.write( "\n" ); document.write( "x = 605*6 = 3630\r
\n" ); document.write( "\n" ); document.write( "Greets,
\n" ); document.write( "Scriptor
\n" ); document.write( "
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