document.write( "Question 619487: Two trains leave Chicago at the same time and in opposite directions. One is going 120MPH and one is going 130MPH. How long before they are 750 miles apart?
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\n" ); document.write( "\n" ); document.write( "I am not sure my equation is correct.\r
\n" ); document.write( "\n" ); document.write( "750/120=6
\n" ); document.write( "750/130= 5.7\r
\n" ); document.write( "\n" ); document.write( "I rounded up and came to conclusion that 6hr would be the average time. Is this correct? If not whats the equation I need to use. Thank you.
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Algebra.Com's Answer #389674 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Train 1: \r
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\n" ); document.write( "\n" ); document.write( "d = rt\r
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\n" ); document.write( "\n" ); document.write( "d = 120t\r
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\n" ); document.write( "\n" ); document.write( "Train 2:\r
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\n" ); document.write( "\n" ); document.write( "d = rt\r
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\n" ); document.write( "\n" ); document.write( "d = 130t\r
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\n" ); document.write( "\n" ); document.write( "So train 1 has traveled 120t miles in t hours and train 2 has traveled 130t miles in t hours.\r
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\n" ); document.write( "\n" ); document.write( "Since they are going in opposite directions (along let's assume a straight track), they will be 120t+130t = 250t miles apart after t hours.\r
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\n" ); document.write( "\n" ); document.write( "We want this distance to be 750, so \r
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\n" ); document.write( "\n" ); document.write( "250t = 750\r
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\n" ); document.write( "\n" ); document.write( "t = 750/250\r
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\n" ); document.write( "\n" ); document.write( "t = 3\r
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\n" ); document.write( "\n" ); document.write( "So in 3 hours, the two trains will be 750 miles apart.
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