document.write( "Question 619397: I can do this when the numbers are whole, but fractions are really throwing me off. Thank you for any help you can provide!!\r
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\n" ); document.write( "\n" ); document.write( "Write the geometric series -9/2+3/2-1/2+1/6-...+1/39366 in summation notation. Then using the formula for the sum of a geometric series, compute the sum.
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Algebra.Com's Answer #389644 by KMST(5328)\"\" \"About 
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\n" ); document.write( "I calculated the common ratio (the ratio of any two consecutive terms) as
\n" ); document.write( "\"r=%28-1%2F2%29%2F%283%2F2%29=%28-1%2F2%29%2A%282%2F3%29=-1%2A2%2F2%2F3=-1%2F3\" \"highlight%28r=-1%2F3%29\"
\n" ); document.write( "(I chose the pair of consecutive terms so as to make my calculation so easy that that I could do in my head. It looks more complicated when I write it out, but I just asked myself what factor multiplied by 3/2 would give me -1/2, and the answer was obvious).
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\n" ); document.write( "Computing that sum is not mental math, though.
\n" ); document.write( "We know that the sum of the first n terms in a geometric sequence is
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\n" ); document.write( "So for the series in the problem, substituting the values found for \"a%5B1%5D%7D%7D%2C+%7B%7B%7Br\" and number of terms
\n" ); document.write( "-9/2+3/2-1/2+1/6-...+1/39366=
\n" ); document.write( "That looks ugly, let's see if we can use common denominators and simplify some powers of 3
\n" ); document.write( "SUM = =\"-3%5E2%2A%283%5E12-1%29%2A3%2F%282%2A3%5E12%2A4%29\"=
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