document.write( "Question 619433: find the center (h,k) and radius, r, of the cirlce. x^2+y^2+6x+8y+9=0 \n" ); document.write( "

Algebra.Com's Answer #389642 by jim_thompson5910(35256) $\"\"$ $\"About$

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x^2+y^2+6x+8y+9=0\r
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\n" ); document.write( "\n" ); document.write( "(x^2+6x)+(y^2+8y)+9=0\r
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\n" ); document.write( "\n" ); document.write( "(x^2+6x+9-9)+(y^2+8y+16-16)+9=0\r
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\n" ); document.write( "\n" ); document.write( "(x^2+6x+9)-9+(y^2+8y+16)-16+9=0\r
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\n" ); document.write( "\n" ); document.write( "(x+3)^2-9+(y+4)^2-16+9=0\r
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\n" ); document.write( "\n" ); document.write( "(x+3)^2+(y+4)^2-16=0\r
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\n" ); document.write( "\n" ); document.write( "(x+3)^2+(y+4)^2=16\r
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\n" ); document.write( "\n" ); document.write( "(x-(-3))^2+(y-(-4))^2=16\r
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\n" ); document.write( "\n" ); document.write( "(x-(-3))^2+(y-(-4))^2 = 4^2\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in (x-h)^2+(y-k)^2=r^2 form where h = -3, k = -4 and r = 4. Note: this conic section is a circle.\r
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\n" ); document.write( "\n" ); document.write( "So the center of this circle is (-3,-4) and it has a radius of 4. \n" ); document.write( "

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