document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619378>Question 619378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given three consecutive odd numbers such that the square of the second number is 104 less than the square of the third number. Find those numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389594 by </B><A HREF=/tutors/aboutme.mpl?userid=bosco20106><B>bosco20106(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bosco20106><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the odd numbers be n, n+2 and n+4.<BR>\n" );
document.write( "=> (n+2)² +104 = (n+4)²<BR>\n" );
document.write( "Expanding the brackets;<BR>\n" );
document.write( "n²+4n+4+104 = n²+8n+16<BR>\n" );
document.write( "Re-arranging the terms;<BR>\n" );
document.write( "n²-n²+4n-8n=16-4-104<BR>\n" );
document.write( "-4n=-92<BR>\n" );
document.write( "n=23<BR>\n" );
document.write( "Therefore, the odd numbers are: 23, (23+2), (23+4)<BR>\n" );
document.write( "i.e. 23, 25, 27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );