document.write( "Question 619302: Can anyone help me with this? I need to show my work but not sure what steps I need to take to solve this.\r
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document.write( "X has a normal distribution with a mean of 80.0 and a standard deviation of 3.5. Find the following probabilities:
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document.write( "(A) P(x < 77.0)
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document.write( "(B) P(75.0 < x < 85.0)
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document.write( "(C) P(x > 85.0) \n" );
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Algebra.Com's Answer #389587 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! X has a normal distribution with a mean of 80.0 and a standard deviation of 3.5. Find the following probabilities: \n" ); document.write( "---- \n" ); document.write( "The measuring stick you have to use to find probabilities \n" ); document.write( "is the z-chart or technology that you have available. \n" ); document.write( "------------------------------- \n" ); document.write( "(A) P(x < 77.0) \n" ); document.write( "z(77) = (77-80)/3.5 = -3/3.5 = -0.8571 \n" ); document.write( "That simply means 77 is 0.8571 standard deviations below the mean. \n" ); document.write( "Now use your z-chart to find the probability to the left of -0.8571 \n" ); document.write( "Ans: normalcdf(-100,-0.8571) = 0.1957 \n" ); document.write( "-------------------------------------------- \n" ); document.write( "(B) P(75.0 < x < 85.0) \n" ); document.write( "z(75) = (75-80)/3.5 = -1.4286 \n" ); document.write( "z(85) = (85-80)/3.5 = +1.4286 \n" ); document.write( "P(75 \n" ); document.write( "(C) P(x > 85.0)= P(z > 1.4286) = normalcdf(1.4286,100) = 0.0766 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |