document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619356>Question 619356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man travels in a motor speed bangka at the rate of 15 kph from his barrio to the city and comes back at the rate of 12 kph. If his total time of travel is 3 hours, find the distance between his barrio to the city. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389580 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a man travels in a motor speed bangka at the rate of 15 kph from his barrio to the city and comes back at the rate of 12 kph. If his total time of travel is 3 hours, find the distance between his barrio to the city.<BR>\n" );
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document.write( "let x=travel time from barrio to city<BR>\n" );
document.write( "3-x=travel time from city to barrio<BR>\n" );
document.write( "distance=travel time*speed<BR>\n" );
document.write( "15x=12(3-x)=36-12x<BR>\n" );
document.write( "27x=36<BR>\n" );
document.write( "x=36/27=4/3 hrs<BR>\n" );
document.write( "Distance between barrio and city=15x=15*4/3=20 km </SPAN>\n" );
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