document.write( "Question 619253: Find vertex, focus, and directrix of the parabola. 1/2y^2 +18x=0 \n" ); document.write( "
Algebra.Com's Answer #389574 by lwsshak3(11628)\"\" \"About 
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Find vertex, focus, and directrix of the parabola.1/2y^2 +18x=0
\n" ); document.write( "Given parabola opens leftwards
\n" ); document.write( "Its equation: (y-k)^2=-4p(x-h), (h,k)= (x,y) coordinates of vertex
\n" ); document.write( "1/2y^2 +18x=0
\n" ); document.write( "1/2y^2 =-18x
\n" ); document.write( "y^2=-36x
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: y=0 or x-axis
\n" ); document.write( "4p=36
\n" ); document.write( "p=8
\n" ); document.write( "focus: (0-p,0)
\n" ); document.write( "=(0-8,0)
\n" ); document.write( "=(-8,0)
\n" ); document.write( "..
\n" ); document.write( "Directrix: x=8 (p units to the right of vertex on the axis of symmetry)\r
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