document.write( "Question 619298: A 5-card hand is dealt from a deck of 52 cards. What is the probability that
\n" ); document.write( "a.) none are queens?
\n" ); document.write( "b.) all are queens?
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Algebra.Com's Answer #389560 by sophxmai(62)\"\" \"About 
You can put this solution on YOUR website!
There are only 4 queens in a deck of cards.
\n" ); document.write( "P(a)= probability that event A occurs
\n" ); document.write( "= (total number of desired outcomes)/(total number of possible outcomes)
\n" ); document.write( "Use combinatorics.\r
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\n" ); document.write( "\n" ); document.write( "The total number of possible outcomes in a) and b) is
\n" ); document.write( "52C5 = 2598960\r
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\n" ); document.write( "\n" ); document.write( "The total number of desired outcomes in a) is
\n" ); document.write( "48C5 = 1712304
\n" ); document.write( "It's 48 because you don't want any queens, and there are 4 queens in a deck of 52\r
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\n" ); document.write( "\n" ); document.write( "The total number of desired outcomes in b) is
\n" ); document.write( "0 because there are only 4 queens in a deck of 52, but you want your 5 card hand to be all queens.\r
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\n" ); document.write( "\n" ); document.write( "So
\n" ); document.write( "a)P(no queens in a 5 card hand)=1712304/2598960=0.659
\n" ); document.write( "b)P(all queens in a 5 card hand)=0/2598960=0
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