document.write( "Question 619298: A 5-card hand is dealt from a deck of 52 cards. What is the probability that
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document.write( "a.) none are queens?
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document.write( "b.) all are queens? \n" );
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Algebra.Com's Answer #389560 by sophxmai(62) You can put this solution on YOUR website! There are only 4 queens in a deck of cards. \n" ); document.write( "P(a)= probability that event A occurs \n" ); document.write( "= (total number of desired outcomes)/(total number of possible outcomes) \n" ); document.write( "Use combinatorics.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The total number of possible outcomes in a) and b) is \n" ); document.write( "52C5 = 2598960\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The total number of desired outcomes in a) is \n" ); document.write( "48C5 = 1712304 \n" ); document.write( "It's 48 because you don't want any queens, and there are 4 queens in a deck of 52\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The total number of desired outcomes in b) is \n" ); document.write( "0 because there are only 4 queens in a deck of 52, but you want your 5 card hand to be all queens.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( "a)P(no queens in a 5 card hand)=1712304/2598960=0.659 \n" ); document.write( "b)P(all queens in a 5 card hand)=0/2598960=0 \n" ); document.write( " |