document.write( "Question 619314: The population P (in millions) of California x years after 2000 can be modeled by P=34e^0.013x.
\n" ); document.write( "a.) Use properties of logarithms to solve this equation for x.
\n" ); document.write( "b.) Use your equation to find x when P=38.Interpret your answer.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #389546 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The population P (in millions) of California x years after 2000 can be modeled by P=34e^0.013x.
\n" ); document.write( "a.) Use properties of logarithms to solve this equation for x.
\n" ); document.write( "P=34e^(0.013x)
\n" ); document.write( "P/34 = e^(0.013x)
\n" ); document.write( "ln(P/34) = 0.013x
\n" ); document.write( "ln(P/34)/0.013 = x
\n" ); document.write( ".
\n" ); document.write( "b.) Use your equation to find x when P=38.Interpret your answer.
\n" ); document.write( "ln(P/34)/0.013 = x
\n" ); document.write( "ln(38/34)/0.013 = x
\n" ); document.write( ".11123/0.013 = x
\n" ); document.write( "8.56 = x
\n" ); document.write( ".
\n" ); document.write( "Year: 2000+8.56 = 2008.56
\n" ); document.write( "The population of California will be 38 million around mid-year of 2008.
\n" ); document.write( "
\n" );