document.write( "Question 619280: During the first part of a trip, a canoeist travels 35 miles at a certain speed. The canoeist travels 14 miles on the second part or the trip at a speed 5 mph slower. The total time for the trip is 2 hours. What is the speed on each part of the trip?\r
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Algebra.Com's Answer #389515 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
During the first part of a trip, a canoeist travels 35 miles at a certain speed. The canoeist travels 14 miles on the second part or the trip at a speed 5 mph slower. The total time for the trip is 2 hours. What is the speed on each part of the trip?
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\n" ); document.write( "1st leg DATA:
\n" ); document.write( "distance = 35 miles ; rate = x mph ; time = d/r = 25/x hrs
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\n" ); document.write( "2nd leg DATA:
\n" ); document.write( "distance = 14 miles ; rate = x-5 mph ; time = d/r = 14/(x-5) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 2 hrs
\n" ); document.write( "25/x + 14/(x-5) = 2 hrs
\n" ); document.write( "25(x-5) + 14x = 2x(x-5)
\n" ); document.write( "25x - 125 + 14x = 2x^2 - 10x
\n" ); document.write( "2x^2 -49x + 125 = 0
\n" ); document.write( "x = 21.607 mph (rate on 1st leg)
\n" ); document.write( "x-5 = 16.607 mph (rate on 2nd leg)
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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