document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619279>Question 619279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem : the length of a rectangle is 4 ft longer than twice the width. If the perimeter is 74 ft. find the length and the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389513 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 4 ft longer than twice the width. If the perimeter is 74 ft. find the length and the width<BR>\n" );
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document.write( "Let width be \"x\"<BR>\n" );
document.write( "Then length is \"2x+4\"<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "P = 2(L + W)<BR>\n" );
document.write( "74 = 2(2x+4 + x)<BR>\n" );
document.write( "37 = 3x+4<BR>\n" );
document.write( "3x = 33<BR>\n" );
document.write( "x = 11 ft (width)<BR>\n" );
document.write( "2x+4 = 26 ft (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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