document.write( "Question 619232: what is the solution to log (6x-2)-log (x-3)=1 \n" ); document.write( "
Algebra.Com's Answer #389477 by Theo(13342)\"\" \"About 
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log(6x-2) - log(x-3) = 1
\n" ); document.write( "log((6x-2)/(x-3) = 1
\n" ); document.write( "10^1 = (6x-2)/(x-3)
\n" ); document.write( "10 (x-3) = 6x-2
\n" ); document.write( "10x-30 = 6x-2
\n" ); document.write( "4x = 28
\n" ); document.write( "x = 7
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\n" ); document.write( "use the following concepts.
\n" ); document.write( "log(a) - log(b) = log(a/b)
\n" ); document.write( "log(a) = y if and only if 10^y = a
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\n" ); document.write( "remember:
\n" ); document.write( "log(a) = log(10,a) = log of a to the base of 10
\n" ); document.write( "this is assumed whenever you say log of something and don't mention the base.
\n" ); document.write( "also:
\n" ); document.write( "log function of calculator implies base of 10\r
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