document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619220>Question 619220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe can do a job in 12 days after he has worked for 4 days he is joined by Casey and it takes them 2 days working together to finish the job. How long would it take Casey to do the whole job herself. \r<BR>\n" );
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document.write( "THIS IS WHAT I DID<BR>\n" );
document.write( "Joe time + Casey time = both working together, but they only do 1/2 the job in a day<BR>\n" );
document.write( "4(1/12) + 1/X = (1 - 4/12)/2<BR>\n" );
document.write( "I get an answer of no solution so my problem must be set up wrong. Can you help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389475 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe finished 1/3 of the job before Casey came, so they finished 2/3 together\r<BR>\n" );
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document.write( "(2/12) + (2/C) = 2/3\r<BR>\n" );
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document.write( "in the 2 days they work together, Joe does another 1/6 of the job (so he does 1/2 total)<BR>\n" );
document.write( "___ this means Casey does 1/2 of the job in 2 days </SPAN>\n" );
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