document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=619210>Question 619210</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would just like to know the steps to solve this problem:<BR>\n" );
document.write( " A square's side is increased by 2 yards, which corresponds to an increase in the area by 36 square yards. How many yards is the side of the initial square?<BR>\n" );
document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389459 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A square's side is increased by 2 yards, which corresponds to an increase in the area by 36 square yards. How many yards is the side of the initial square?<BR>\n" );
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document.write( "The original side = s<BR>\n" );
document.write( "The original area = s^2<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28s%2B2%29%5E2+=+s%5E2+%2B+36 ALIGN=MIDDLE  ALT=\"%28s%2B2%29%5E2+=+s%5E2+%2B+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+%2B+4s+%2B+4+=+s%5E2+%2B+36 ALIGN=MIDDLE  ALT=\"s%5E2+%2B+4s+%2B+4+=+s%5E2+%2B+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "4s + 4 = 36<BR>\n" );
document.write( "s = 8<BR>\n" );
document.write( " </SPAN>\n" );
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