document.write( "Question 619119: The equation is y=(x+2)^2+k where k is a constant.
\n" ); document.write( "a)Find k when its tangent at x=1 passes through (0,0).
\n" ); document.write( "b)Find k when the quadratic is tangent to y=-x^2 \n" ); document.write( "

Algebra.Com's Answer #389436 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
\n" );
document.write( "Hi, Re TY, Note: completed the exercise by demonstrating using the 1st  derivative.
\n" );
document.write( "The equation is y=(x+2)^2+k where k is a constant.
\n" );
document.write( "a)Find k when its tangent at x=1 passes through (0,0). 
\n" );
document.write( "y=(x+2)^2+k , y' = 2(x+2), x=1, m = 6, tangent line is y = 6x, Tangent at(1,6)
\n" );
document.write( "6 = (1+2)^2 + k, k = 
\n" );
document.write( "b)Find k when the quadratic is tangent to y= -x^2, k = -2 (see 2nd graph)
\n" );
document.write( " Taking 1st derivatives of both:  2(x+2) = -2x, x = -1, tangent at (-1,-1)
\n" );
document.write( " -1 = (-1+2)^2 + k, k = -2
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "

\n" );