document.write( "Question 619174: seven times a two digit number is the same as four times the number obtained on interchanging the digits of the given number . if one digit of the given number exceeds the other by 3,find the number. \n" ); document.write( "
Algebra.Com's Answer #389424 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! seven times a two digit number is the same as four times the number obtained on interchanging the digits of the given number. \n" ); document.write( " if one digit of the given number exceeds the other by 3, find the number. \n" ); document.write( ": \n" ); document.write( "10a + b = \"the number\" \n" ); document.write( ": \n" ); document.write( "The equation: \n" ); document.write( "7(10a + b) = 4(10b + a) \n" ); document.write( "70a + 7b = 40b + 4a \n" ); document.write( "70a - 4a = 40b - 7b \n" ); document.write( "66a = 33b \n" ); document.write( ": \n" ); document.write( "\"one digit of the given number exceeds the other by 3\" \n" ); document.write( "We know b is the larger digit from the above equation \n" ); document.write( "b - a = 3 \n" ); document.write( "b = (a+3) \n" ); document.write( ": \n" ); document.write( "replace b with (a+3) \n" ); document.write( "66a = 33(a+3) \n" ); document.write( "66a = 33a + 99 \n" ); document.write( "66a - 33a = 99 \n" ); document.write( "33a = 99 \n" ); document.write( "a = 3 \n" ); document.write( ": \n" ); document.write( "You can find b, check the solution in the 1st statement \n" ); document.write( " \n" ); document.write( " |