document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618935>Question 618935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389309 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve<BR>\n" );
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document.write( "Draw a picture of a normal curve.<BR>\n" );
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document.write( "Center 34% around the mean, keeping 17% to the left and 17% to the right<BR>\n" );
document.write( "of the mean.<BR>\n" );
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document.write( "Then the left tail has 0.50-0.17 = 0.33 = 33% of the data.<BR>\n" );
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document.write( "Find the corresponding z-value:<BR>\n" );
document.write( "invNorm(0.33) = -0.4399<BR>\n" );
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document.write( "The corresponding value to the right of the mean is +0.4399<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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