document.write( "Question 618960: Find the standard form of the equation of the specified hyperbola.\r
\n" ); document.write( "\n" ); document.write( "49x^2 - 196x - 36y^2 + 504y - 3332 = 0
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Algebra.Com's Answer #389207 by lwsshak3(11628)\"\" \"About 
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Find the standard form of the equation of the specified hyperbola.
\n" ); document.write( "49x^2 - 196x - 36y^2 + 504y - 3332 = 0
\n" ); document.write( "complete the square
\n" ); document.write( "49(x^2-4x+4)-36(y^2-14y+49)= 3332+196-1764
\n" ); document.write( "49(x-2)^2-36(y-7)^2=1764
\n" ); document.write( "divide by 1764
\n" ); document.write( "Equation of given hyperbola: (x-2)^2/36-(y-7)^2/49=1
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