document.write( "Question 618962: Find the equations of the asymptotes of the hyperbola.\r
\n" ); document.write( "\n" ); document.write( "25y^2 - 16x -400 = 0
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Algebra.Com's Answer #389204 by lwsshak3(11628)\"\" \"About 
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Find the equations of the asymptotes of the hyperbola.
\n" ); document.write( "25y^2 - 16x^2 -400 = 0
\n" ); document.write( "25y^2-16x^2=400
\n" ); document.write( "Divide by 400
\n" ); document.write( "y^2/16-x^2/25=1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis
\n" ); document.write( "Its form of equation: (y-k)^2/a^2-(x-h)^2=1, (h,k)=(x,y) coordinates of the center.
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (0,0)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "b^2=25
\n" ); document.write( "b=√25=5
\n" ); document.write( "..
\n" ); document.write( "Asymptotes are straight lines that intersect at the center(0,0). Equation: y=mx+b, m=slope, b=y intercept
\n" ); document.write( "Slopes of asymptotes for hyperbolas with vertical transverse axis=a/b=4/5
\n" ); document.write( "Equation of asymptote with slope<0
\n" ); document.write( "y=-4x/5+b
\n" ); document.write( "since asymptote go thru center, y-intercept, b=0
\n" ); document.write( "so, equation: y=-4x/5
\n" ); document.write( "..
\n" ); document.write( "By the same reasoning,
\n" ); document.write( "Equation of asymptote with slope>0
\n" ); document.write( "y=4x/5
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