document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618944>Question 618944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simply the experssion <BR>\n" );
document.write( "(2a-3) (5a+4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389198 by </B><A HREF=/tutors/aboutme.mpl?userid=barai><B>barai(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=barai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=barai><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Expand then simplify by collecting like terms\r<BR>\n" );
document.write( "\n" );
document.write( "First times the first number together in each of the brackets.<BR>\n" );
document.write( "(in this case times 2a by 5a)= 10a^\r<BR>\n" );
document.write( "\n" );
document.write( "Secondly times the first number in the first bracket by the last number in the seocnd bracket.<BR>\n" );
document.write( "(times 2a by 400 = 8a\r<BR>\n" );
document.write( "\n" );
document.write( "Third times the second number in the first bracket by the first in the second bracket.<BR>\n" );
document.write( "(times -3 by 5a)= -15a\r<BR>\n" );
document.write( "\n" );
document.write( "lastly times the last two numbers of each bracket together.<BR>\n" );
document.write( "(times -3 by 4)= -12\r<BR>\n" );
document.write( "\n" );
document.write( "Then collect the like terms of expanded expression 10a^ +8a-15a-12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "=10a^-7a-12    </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );