document.write( "Question 618933: Divide 32 into two parts such that five times of the first part exceeds four times of the second part by twenty five.
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Algebra.Com's Answer #389194 by Maths68(1474) $\"\"$ $\"About$

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Let x be the first part
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\n" ); document.write( "\n" ); document.write( "Five times of the first part exceeds four times of the second part by twenty five
\n" ); document.write( "5x=4(32-x)+25
\n" ); document.write( "5x=128-4x+25
\n" ); document.write( "5x=153-4x
\n" ); document.write( "5x+4x=153
\n" ); document.write( "9x=153
\n" ); document.write( "9x/9=153/9
\n" ); document.write( "x=17\r
\n" ); document.write( "\n" ); document.write( "First Part = 17
\n" ); document.write( "Second Part = 32-17=15\r
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\n" ); document.write( "5 times of first part = 5(17)=85
\n" ); document.write( "4 times of second part = 4(15)=60\r
\n" ); document.write( "\n" ); document.write( "5times of first=4times of the second part + 25
\n" ); document.write( "85=60+25
\n" ); document.write( "85=85\r
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