document.write( "Question 618833: A) Build a pattern using tiles for y=x^2-4x+3
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document.write( "B) Show how your pattern would look for x= -2,-1,0,1,2 (do I simply plug these number in the quadratic equation?!)
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document.write( "C) Find the y-intercept and the x- intercept (if any), the turning point (vertex) and the range.
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Algebra.Com's Answer #389145 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'm not sure what sort of new math folderol \"build a pattern using tiles\" is supposed to be, but yes, plug each of the given \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Set the function equal to zero and then solve the resulting quadratic equation for the two roots. The \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the lead coefficient is positive, the parabola opens upward. Hence the vertex is a minimum of the function. Therefore the lower limit of the range is the value of the function at the vertex, i.e., the number you calculated in the previous step. Since this is a parabola and the domain has not been otherwise restricted, there is no upper bound to the range.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |