document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618772>Question 618772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Convert the Polar form (2,-pie/6) to a complex number in the form a+ib. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #389101 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=389101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -pi/6 gives a 30º reference angle in quadrant IV\r<BR>\n" );
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document.write( "a = 2[cos(-30º)] = 2 * [(&#8730;3) / 2] = &#8730;3\r<BR>\n" );
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document.write( "b = 2[sin(-30º)] = 2 * (-1/2) = -1\r<BR>\n" );
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document.write( "&#8730;3 - i </SPAN>\n" );
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