document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=57193>Question 57193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 74+x=218 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38905 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The goal is to get x all by itself on one side of the = sign within the rules of algebra.  Whatever you do to get x all by itself you have to do to both sides of the equation.<BR>\n" );
document.write( "74+x=218<BR>\n" );
document.write( "-74+74+x=218-74<BR>\n" );
document.write( "0+x=144<BR>\n" );
document.write( "x=144<BR>\n" );
document.write( ":<BR>\n" );
document.write( "To check your answer, substitute 144 in for x in the original equation and see if both sides =.<BR>\n" );
document.write( "74+(144)=218<BR>\n" );
document.write( "74+144=218<BR>\n" );
document.write( "218=218  We're right!!!<BR>\n" );
document.write( "Happy Calculating!!!<BR>\n" );
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