document.write( "Question 618676: A man is three times as old as his son. Eight years ago the sum of their ages was 36. What are their present ages? \n" ); document.write( "

Algebra.Com's Answer #389023 by vleith(2983) $\"\"$ $\"About$

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let the mans age today be m. Let the son's age today be s
\n" ); document.write( " $\"m+=+3s\"$
\n" ); document.write( "eight years ago, the man was $\"m-8\"$ and his son was $\"s-8\"$
\n" ); document.write( " $\"%28m-8%29%2B%28s-8%29+=+36\"$
\n" ); document.write( " $\"m+%2B+s+-+16+=+36\"$
\n" ); document.write( " $\"m+%2B+s+=+52\"$ substitute in the value for m from the first equation above
\n" ); document.write( " $\"3s+%2B+s+=+52\"$
\n" ); document.write( " $\"4s+=+52\"$
\n" ); document.write( " $\"s+=+13\"$ the son is 13 today
\n" ); document.write( "His Dad is 3*13 = 39 \n" ); document.write( "

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