document.write( "Question 618620: The amount of carbon-14 located in animal bones after t years is given by P(t)=Poe^-0.00012t a bone has lost 19% of its carbon-14 how old is the bone? How old is a bone that has lost 23%? \n" ); document.write( "
Algebra.Com's Answer #389009 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The amount of carbon-14 located in animal bones after t years is given by P(t)=Poe^-0.00012t a bone has lost 19% of its carbon-14 how old is the bone? \n" ); document.write( ". \n" ); document.write( "P(t)=Poe^-0.00012t \n" ); document.write( "(1-.19)Po = Poe^(-0.00012t) \n" ); document.write( ".81Po = Poe^(-0.00012t) \n" ); document.write( "dividing both sides by Po: \n" ); document.write( ".81 = e^(-0.00012t) \n" ); document.write( "take ln of both sides: \n" ); document.write( "ln(.81) = -0.00012t \n" ); document.write( "ln(.81)/(-0.00012) = t \n" ); document.write( "1756 years = t \n" ); document.write( ". \n" ); document.write( "How old is a bone that has lost 23%? \n" ); document.write( "P(t)=Poe^-0.00012t \n" ); document.write( "(1-.23)Po = Poe^(-0.00012t) \n" ); document.write( "(.77)Po = Poe^(-0.00012t) \n" ); document.write( "dividing both sides by Po: \n" ); document.write( ".77 = e^(-0.00012t) \n" ); document.write( "take ln of both sides: \n" ); document.write( "ln(.77) = -0.00012t \n" ); document.write( "ln(.77)/(-0.00012) = t \n" ); document.write( "2178 years = t \n" ); document.write( " \n" ); document.write( " |