document.write( "Question 618465: how much of an alloy that is 40% copper should be mixed with 100 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper? \n" ); document.write( "

Algebra.Com's Answer #388982 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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how much of an alloy that is 40% copper should be mixed with 100 ounces of an alloy that is 70% copper in order to get an alloy that is 50% copper?
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\n" ); document.write( "Let x amt of 40% alloy
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\n" ); document.write( ".40x + .70(100) = .50(x+100)
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\n" ); document.write( ".40x + 70 = .50x + 50
\n" ); document.write( "70 - 50 = .50x - .40x
\n" ); document.write( "20 = .10x
\n" ); document.write( "x = 20/.1
\n" ); document.write( "x = 200 oz of 40% alloy
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