document.write( "Question 618534: 1. \n" ); document.write( "\n" ); document.write( "2. \n" ); document.write( "\n" ); document.write( "3. \n" ); document.write( "\n" ); document.write( "4. \n" ); document.write( "\n" ); document.write( "5.The measure of < B, the supplement of \n" ); document.write( "
Algebra.Com's Answer #388975 by stanbon(75887)\"\" \"About 
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1. \n" ); document.write( "Equations:
\n" ); document.write( "A = 2B
\n" ); document.write( "A + B = 90
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\n" ); document.write( "Substitute for \"A\" and solve for \"B\":
\n" ); document.write( "2B + B = 90
\n" ); document.write( "3B = 90
\n" ); document.write( "B = 30 degrees
\n" ); document.write( "So A = 2B = 60 degrees
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\n" ); document.write( "\n" ); document.write( "2. \n" ); document.write( "Equations:
\n" ); document.write( "A = (1/2)B
\n" ); document.write( "A + B = 90
\n" ); document.write( "Substitute for \"A: and solve for \"B\":
\n" ); document.write( "(1/2)B + B = 90
\n" ); document.write( "3/2 B = 90
\n" ); document.write( "B = (2/3)90 = 60
\n" ); document.write( "So A = 30
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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