document.write( "Question 618505: A tourist can bicycle 33 miles in the same time as he can walk 12 miles. If he can ride 7 mph faster than he can walk, how much time should he allow to walk a 30-mile trail? \n" ); document.write( "

Algebra.Com's Answer #388958 by John10(297) $\"\"$ $\"About$

You can put this solution on YOUR website!
A tourist can bicycle 33 miles in the same time as he can walk 12 miles. If he can ride 7 mph faster than he can walk, how much time should he allow to walk a 30-mile trail?\r
\n" ); document.write( "\n" ); document.write( "____________________________________________________\r
\n" ); document.write( "\n" ); document.write( "Let x be the speed that he walks\r
\n" ); document.write( "\n" ); document.write( "since he can bicycle 33 miles AS SAME TIME as he walks 12 miles.\r
\n" ); document.write( "\n" ); document.write( "we have the equation for time:\r
\n" ); document.write( "\n" ); document.write( "33/(x + 7) = 12/x
\n" ); document.write( "33x = 12(x + 7)
\n" ); document.write( "33x = 12x + 84
\n" ); document.write( "33x - 12x = 84
\n" ); document.write( "21x = 84
\n" ); document.write( "x = 4 mph\r
\n" ); document.write( "\n" ); document.write( "If the trail is 30 miles then the time he must walk is:\r
\n" ); document.write( "\n" ); document.write( "t = distance / speed = 30/4 = 7.5 hours or 7 hours and 30 minutes.\r
\n" ); document.write( "\n" ); document.write( "Hope it helps you:)\r
\n" ); document.write( "\n" ); document.write( "John10 \n" ); document.write( "

\n" );