document.write( "Question 618495: How do you find the vertex, focus, directrix, and axis of symmetry of the parabola?\r
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document.write( "x^2-2x+8y+9=0 \n" );
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Algebra.Com's Answer #388952 by John10(297)![]() ![]() You can put this solution on YOUR website! Hint: \n" ); document.write( "Convert your equation in form: (x - h)^2 = 4p(y - k)\r \n" ); document.write( "\n" ); document.write( "where \r \n" ); document.write( "\n" ); document.write( "(h,k) is the vertex \n" ); document.write( "(h, k + p) is the focus \n" ); document.write( "y = k - p is the directrix \n" ); document.write( "x = h is the axis of symmetry\r \n" ); document.write( "\n" ); document.write( "I'll help you to convert it: \n" ); document.write( "x^2 - 2x + 8y +9 = 0 \n" ); document.write( "x^2 - 2x + 1 = -8y - 8 \n" ); document.write( "(x - 1)^2 = -8( y + 1)\r \n" ); document.write( "\n" ); document.write( "You can follow up from here. Good luck:)\r \n" ); document.write( "\n" ); document.write( "John10 \n" ); document.write( " \n" ); document.write( " |