document.write( "Question 618461: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
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document.write( "y = 3x2 12x + 12
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Algebra.Com's Answer #388931 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. \n" ); document.write( "y = 3x2+12x + 12 \n" ); document.write( "complete the square \n" ); document.write( "y=3(x^2+4x+4)+12-12 \n" ); document.write( "y=3(x+2)^2 \n" ); document.write( "This is an equation of a parabola that opens upwards. \n" ); document.write( "vertex: (-2,0) \n" ); document.write( "vertex lies on the x-axis \n" ); document.write( " |