document.write( "Question 618461: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
\n" ); document.write( "y = 3x2 12x + 12
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Algebra.Com's Answer #388931 by lwsshak3(11628)\"\" \"About 
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Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
\n" ); document.write( "y = 3x2+12x + 12
\n" ); document.write( "complete the square
\n" ); document.write( "y=3(x^2+4x+4)+12-12
\n" ); document.write( "y=3(x+2)^2
\n" ); document.write( "This is an equation of a parabola that opens upwards.
\n" ); document.write( "vertex: (-2,0)
\n" ); document.write( "vertex lies on the x-axis
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