document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=618384>Question 618384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an electrical contractor is planning to complete a lighting job by useing two separate crews.  Both crews working together would require 20 days to complete the entire job.  The first crew working alone would require 60 days to complete the entire job.  Assume that all workers maintained their same rate of doing the work, whether working individulally or collectively.  How many days would it take for the second crew, working alone to complete the job? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #388863 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=388863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 20/60+20/x=1<BR>\n" );
document.write( "20/x=2/3<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "check<BR>\n" );
document.write( "20/60+20/30=1<BR>\n" );
document.write( "1/3+2/3=1<BR>\n" );
document.write( "1=1<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );