document.write( "Question 618385: 5. How much pure antifreeze must be added to 12 gallons of
\n" ); document.write( "20% antifreeze to make a 40% antifreeze solution?
\n" ); document.write( "a.2 gallons
\n" ); document.write( "b.4 gallons
\n" ); document.write( "c.6 gallons
\n" ); document.write( "d.8 gallons\r
\n" ); document.write( "\n" ); document.write( "6. One computer printer can print a company's mailing labels in
\n" ); document.write( "40 minutes. A second printer would take 60 minutes to print the labels. How
\n" ); document.write( "long would it take the two printers, operating together, to print the labels?
\n" ); document.write( "a.30 minutes
\n" ); document.write( "b.24 minutes
\n" ); document.write( "c.50 minutes
\n" ); document.write( "d.32 minutes \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #388843 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "How much pure antifreeze\"x\" must be added to 12 gallons of
\n" );
document.write( " 20% antifreeze to make a 40% antifreeze solution?            
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document.write( "            antifreeze = antifreeze
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document.write( "\"+x+%2B+.20%2A12+=+.40%2812%2Bx%29\"
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document.write( " \".60x+=+.20%2A12\"
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document.write( " \"+x+=+.20%2A12%2F.6\"
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document.write( "  x = 4 gal
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document.write( "One computer printer can print a company's mailing labels in
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document.write( " 40 minutes..A second printer in 60 minutes   
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document.write( "Time \"x\"Togeiher: PER min KEY
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document.write( " 1/40 + 1/60 = 1/x
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document.write( "  60x + 40x = 2400   
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document.write( "    100x = 2400    |Multiplying thru by 2400x so as all denominators = 1
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document.write( "       x = 24 min \n" );
document.write( "
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