document.write( "Question 57169: Two Jets are traveling torward each otherand are 4000km apart. The rate of one jet is 100 km/h faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of the faster jet \n" ); document.write( "
Algebra.Com's Answer #38882 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! SORRY DIDN'T READ THE ENTIRE PROBLEM. THEY ARE ASKING FOR THE FASTEST WHICH WOULD BE 750=100 OR 850 KM/H.\r \n" ); document.write( "\n" ); document.write( "DISTANCE = RATE TIMES TIME \n" ); document.write( "4000=[X+(X+100)]2.5 \n" ); document.write( "4000=(2X+100)2.5 \n" ); document.write( "4000=5X+250 \n" ); document.write( "5X=4000-250 \n" ); document.write( "5X=3750 \n" ); document.write( "X=3750/5 \n" ); document.write( "X=750 \n" ); document.write( "PROOF \n" ); document.write( "4000=(750+850)2.5 \n" ); document.write( "4000=1600*2.5 \n" ); document.write( "4000=4000 \n" ); document.write( " |